U 9%eJ@s^dZddlZddlmZmZmZddlmZmZm Z ddl m Z ddl m Z mZmZmZddlmZmZmZmZddlmZdd lmZdd lmZmZdd lmZdd lm Z m!Z!m"Z"dd l#m$Z$ddl%m&Z&m'Z'ddl(m)Z)m*Z*ddl+m,Z,ddZ-ddZ.ddZ/d)ddZ0ddZ1ddZ2dej3dfdd Z4d!d"Z5d*d#d$Z6d%d&Z7gfd'd(Z8dS)+ztjgS|tj krPtj gSt d||j ddg}}|dkr|D]\}}t ||}||qzn|dkrtj}|tjdfgD]$\} }t || d d }||| }qnJ|dkrd} nd } d \} } |d krd} nD|d kr"d } n4|dkr6d\} } n |dkrJd\} } n td|tjd } } t|D]\}}|dr| | kr|dt || | | | || } } } nT| | kr| s|dt || d | |d } } n"| | krj| rj|dt ||qj| | kr.|dt tj| d | |S)aSolve a polynomial inequality with rational coefficients. Examples ======== >>> from sympy import solve_poly_inequality, Poly >>> from sympy.abc import x >>> solve_poly_inequality(Poly(x, x, domain='ZZ'), '==') [{0}] >>> solve_poly_inequality(Poly(x**2 - 1, x, domain='ZZ'), '!=') [Interval.open(-oo, -1), Interval.open(-1, 1), Interval.open(1, oo)] >>> solve_poly_inequality(Poly(x**2 - 1, x, domain='ZZ'), '==') [{-1}, {1}] See Also ======== solve_poly_inequalities z8For efficiency reasons, `poly` should be a Poly instancer%could not determine truth value of %sF)Zmultiple==!=T)NF><>=)r#T<=)r$Tz'%s' is not a valid relation) isinstancer ValueErroras_expr is_numberr rtrueRealsfalseEmptySetNotImplementedErrorZ real_rootsr appendNegativeInfinityInfinityZLCreversedinsert)Zpolyreltreals intervalsroot_intervalleftrightsignZeq_signequalZ right_openZ multiplicityrCY/var/www/html/Darija-Ai-API/env/lib/python3.8/site-packages/sympy/solvers/inequalities.pysolve_poly_inequalitysx                      rEcCstdd|DS)aSolve polynomial inequalities with rational coefficients. Examples ======== >>> from sympy import Poly >>> from sympy.solvers.inequalities import solve_poly_inequalities >>> from sympy.abc import x >>> solve_poly_inequalities((( ... Poly(x**2 - 3), ">"), ( ... Poly(-x**2 + 1), ">"))) Union(Interval.open(-oo, -sqrt(3)), Interval.open(-1, 1), Interval.open(sqrt(3), oo)) cSsg|]}t|D]}|qqSrC)rE).0psrCrCrD ~s z+solve_poly_inequalities..)r)ZpolysrCrCrDsolve_poly_inequalitiespsrJcCstj}|D]}|sq ttjtjg}|D]\\}}}t|||}t|d}g} t||D]&\} } | | } | tjk r\| | q\| }g} |D]*} |D] } | | 8} q| tjk r| | q| }|s(qq(|D]} | | }qq |S)a3Solve a system of rational inequalities with rational coefficients. Examples ======== >>> from sympy.abc import x >>> from sympy import solve_rational_inequalities, Poly >>> solve_rational_inequalities([[ ... ((Poly(-x + 1), Poly(1, x)), '>='), ... ((Poly(-x + 1), Poly(1, x)), '<=')]]) {1} >>> solve_rational_inequalities([[ ... ((Poly(x), Poly(1, x)), '!='), ... ((Poly(-x + 1), Poly(1, x)), '>=')]]) Union(Interval.open(-oo, 0), Interval.Lopen(0, 1)) See Also ======== solve_poly_inequality r!) rr1r r4r5rE itertoolsproduct intersectr3union)eqsresult_eqsZglobal_intervalsnumerdenomr8Znumer_intervalsZdenom_intervalsr;Znumer_intervalZglobal_intervalr>Zdenom_intervalrCrCrDsolve_rational_inequalitiess:        rTTc sd}g}|rtjntj}|D]^}g}|D]@}t|trD|\}} n&|jr`|j|j|j}} n |d}} |tj krtj tj d} } } n0|tj krtj tj d} } } n| \} } zt| | f\\} } } Wn tk rttdYnX| jjs| | d} } }| j} | jsZ| jsZ| | }t|d| }|t|ddM}q*|| | f| fq*|r||q|r|t|M}tfdd|Dg}||8}|s|r|}|r|}|S) a8Reduce a system of rational inequalities with rational coefficients. Examples ======== >>> from sympy import Symbol >>> from sympy.solvers.inequalities import reduce_rational_inequalities >>> x = Symbol('x', real=True) >>> reduce_rational_inequalities([[x**2 <= 0]], x) Eq(x, 0) >>> reduce_rational_inequalities([[x + 2 > 0]], x) -2 < x >>> reduce_rational_inequalities([[(x + 2, ">")]], x) -2 < x >>> reduce_rational_inequalities([[x + 2]], x) Eq(x, -2) This function find the non-infinite solution set so if the unknown symbol is declared as extended real rather than real then the result may include finiteness conditions: >>> y = Symbol('y', extended_real=True) >>> reduce_rational_inequalities([[y + 2 > 0]], y) (-2 < y) & (y < oo) Tr!z only polynomials and rational functions are supported in this context. Fr) relationalcs6g|].}|D]$\\}}}|r ||jfdfq qS)r!)hasone)rFindr=genrCrDrIs  z0reduce_rational_inequalities..)rr/r1r*tupleZ is_Relationallhsrhsrel_opr.ZeroOner0Ztogetheras_numer_denomrrrdomainZis_ExactZto_exactZ get_exactZis_ZZZis_QQr solve_univariate_inequalityr3rTZevalf as_relational)exprsr\rUexactrOZsolution_exprsrQexprr8rRrSoptrdexcluderCr[rDreduce_rational_inequalitiessX                rmcs|jdkrttdfddddd}g}|D]D\}}||krZt|d|}nt| d||}||g|q8t||S) aReduce an inequality with nested absolute values. Examples ======== >>> from sympy import reduce_abs_inequality, Abs, Symbol >>> x = Symbol('x', real=True) >>> reduce_abs_inequality(Abs(x - 5) - 3, '<', x) (2 < x) & (x < 8) >>> reduce_abs_inequality(Abs(x + 2)*3 - 13, '<', x) (-19/3 < x) & (x < 7/3) See Also ======== reduce_abs_inequalities Fzs Cannot solve inequalities with absolute values containing non-real variables. csg}|js|jrP|j|jD]0}|}|s2|}qfddt||D}qn|jr|jjsjt d| fdd|j Dnht |t r|jd}|D]>\}}|||t|dgf|| |t|dgfqn |gfg}|S)Ncs*g|]"\\}}\}}||||fqSrCrC)rFrjcondsZ_exprZ_conds)oprCrDrICszBreduce_abs_inequality.._bottom_up_scan..z'Only Integer Powers are allowed on Abs.c3s|]\}}||fVqdSNrC)rFrjrn)rYrCrD JszAreduce_abs_inequality.._bottom_up_scan..r)Zis_AddZis_MulfuncargsrKrLis_Powexp is_Integerr+extendbaser*rr3r r )rjrgargrirn_bottom_up_scan)rYrorDr{7s,         z.reduce_abs_inequality.._bottom_up_scanr%r'r&r(r)is_extended_real TypeErrorrkeysr r3rm)rjr8r\mapping inequalitiesrnrCrzrDreduce_abs_inequalitys     rcstfdd|DS)aReduce a system of inequalities with nested absolute values. Examples ======== >>> from sympy import reduce_abs_inequalities, Abs, Symbol >>> x = Symbol('x', extended_real=True) >>> reduce_abs_inequalities([(Abs(3*x - 5) - 7, '<'), ... (Abs(x + 25) - 13, '>')], x) (-2/3 < x) & (x < 4) & (((-oo < x) & (x < -38)) | ((-12 < x) & (x < oo))) >>> reduce_abs_inequalities([(Abs(x - 4) + Abs(3*x - 5) - 7, '<')], x) (1/2 < x) & (x < 4) See Also ======== reduce_abs_inequality csg|]\}}t||qSrC)r)rFrjr8r[rCrDrIysz+reduce_abs_inequalities..r)rgr\rCr[rDreduce_abs_inequalitiesds rFc( sddlm}|tjdkr*ttdn2|tjk r\td|d|}|rX| }|S}|}j dkrtj }|s||S| |Sj dkrt ddd z |iWn tk rttd YnXd}tjkr|}ntjkrtj }njj} t| } | tjkrVt| } | d} | tjkrB|}n| tjkrtj }n| dk rt| |} j} | d kr| jdr|}n| jdstj }n6| d kr| jdr|}n| jdstj }|j|j}}||tjkrtd| dd|}|}|dkr| \}}z>|jkrNt | jd krNt!t"| |}|dkrht!Wn6t!tfk rttd#t$dYnXt| fdd}g}|D]}|%t"||q|st&|}djkojdk}zt'|j(t)|j|j}t)||t*|t|j|j|j|k|j|k}t+dd|Dr~t,|ddd}nZt-|dd}|drtz"|d}t |d krt.|}Wntk rtYnXWntk rtdYnXtj}t/tjkrd}t)}z4t0t/|}t1|tsp|D].}||kr>||r>|j r>|t)|7}q>n|j|j}} t,|t)| D]}||}!|| kr.||}"t2||}#|#|kr.|#j r.||#r.|!r|"r|t||7}n@|!r|t3||7}n(|"r|t4||7}n|t5||7}|}q|D]}$|t)|$8}q:Wn tk rptj}d}YnX|tj krt!td#||f||}tj g}%|j}||kr||r|j6r|%7t)||D]~}&|&} |t2|| r |%7t|| dd|&|kr"|8|&n6|&|kr@|8|&||&}'n|}'|'rX|%7t)|&| }q|j} | |kr|| r| j6r|%7t)| |t2|| r|%7t5|| t/tjkr|r||}nt9t:|%||#|}|s|S| |S)aTSolves a real univariate inequality. Parameters ========== expr : Relational The target inequality gen : Symbol The variable for which the inequality is solved relational : bool A Relational type output is expected or not domain : Set The domain over which the equation is solved continuous: bool True if expr is known to be continuous over the given domain (and so continuous_domain() does not need to be called on it) Raises ====== NotImplementedError The solution of the inequality cannot be determined due to limitation in :func:`sympy.solvers.solveset.solvify`. Notes ===== Currently, we cannot solve all the inequalities due to limitations in :func:`sympy.solvers.solveset.solvify`. Also, the solution returned for trigonometric inequalities are restricted in its periodic interval. See Also ======== sympy.solvers.solveset.solvify: solver returning solveset solutions with solve's output API Examples ======== >>> from sympy import solve_univariate_inequality, Symbol, sin, Interval, S >>> x = Symbol('x') >>> solve_univariate_inequality(x**2 >= 4, x) ((2 <= x) & (x < oo)) | ((-oo < x) & (x <= -2)) >>> solve_univariate_inequality(x**2 >= 4, x, relational=False) Union(Interval(-oo, -2), Interval(2, oo)) >>> domain = Interval(0, S.Infinity) >>> solve_univariate_inequality(x**2 >= 4, x, False, domain) Interval(2, oo) >>> solve_univariate_inequality(sin(x) > 0, x, relational=False) Interval.open(0, pi) rdenomsFz| Inequalities in the complex domain are not supported. Try the real domain by setting domain=S.Reals)rU continuousNr\TZ extended_realz When gen is real, the relational has a complex part which leads to an invalid comparison like I < 0. r|)r%r'r#z The inequality, %s, cannot be solved using solve_univariate_inequality. xcst|}z|d}Wntk r:tj}YnX|tjtjfkrP|S|jdkr`tjS|d}|j r||dSt d|dS)NrFr)z!relationship did not evaluate: %s) subsrrrr~rr0r.r}rYZ is_comparabler2)rvrZ expanded_erjr\rCrDvalids     z*solve_univariate_inequality..valid=r"css|] }|jVqdSrp)r-)rFrrCrCrDrq>sz.solve_univariate_inequality..) separatedcSs|jSrpr})rrCrCrDAz-solve_univariate_inequality..z'sorting of these roots is not supportedz %s contains imaginary parts which cannot be made 0 for any value of %s satisfying the inequality, leading to relations like I < 0. );sympy.solvers.solversrZ is_subsetrr/r2rre intersectionrfr}r1rxreplacer~r.r0r^r_rrarrrrr`supinfr5r rMrc free_symbolslenr+rrrrwrsetboundaryrlistallrrsortedrrr*_ptZRopenZLopenopen is_finiter3removerr)(rjr\rUrdrrrvZ_genZ_domaineZperiodconstZfranger8rrrYrZZsolnsrZ singularitiesZ include_xZdiscontinuitiesZcritical_pointsr:ZsiftedZ make_realcheckZim_solazstartendZ valid_startZvalid_zptrHZsol_setsr_validrCrrDre}sT9                                          recCs|js|js||d}n|jr.|jr.tj}n|jr>|jdksN|jrV|jdkrVtd|jrb|jsn|jrx|jrx||}}|jr|jr|d}q|jr|tj}q|d}n0|jr|jr|tj}n|jr|d}n|d}|S)z$Return a point between start and endr)Nz,cannot proceed with unsigned infinite valuesr#) is_infiniterraZis_extended_positiver+Zis_extended_negativeZHalf)rrrrCrCrDrs:         rc Csddlm}||jkr|S|j|kr*|j}|j|krD||jjkrD|Sdd}d}tj}|j|j}zBt||}| dkr| | d}n|s| dkrt Wn0t t fk r|szt|gg|}Wnt k rt||}YnX||||} | tjkr.||||tjkr.|||kd}|||| } | tjkr|||| tjkr|| |kd}||| kd}|tjkr| tjkr||kn||k}| tjk rt| |k|}nt|}YnXg} |dkrn| } d} | j|dd\}}| |8} | |8} t| }|j|d d\}} |jd ksd|j|jkrTdkrnnn|jd krn|} tj}| |} |jr| | | }n|j | | }||j||jB}||}||D]T}tt|d||d }t|tr|j|kr||||jtjkr| |q| |fD]N}||||tjkr||||tjk r| ||kr`||kn||kq| |t| S) aReturn the inequality with s isolated on the left, if possible. If the relationship is non-linear, a solution involving And or Or may be returned. False or True are returned if the relationship is never True or always True, respectively. If `linear` is True (default is False) an `s`-dependent expression will be isolated on the left, if possible but it will not be solved for `s` unless the expression is linear in `s`. Furthermore, only "safe" operations which do not change the sense of the relationship are applied: no division by an unsigned value is attempted unless the relationship involves Eq or Ne and no division by a value not known to be nonzero is ever attempted. Examples ======== >>> from sympy import Eq, Symbol >>> from sympy.solvers.inequalities import _solve_inequality as f >>> from sympy.abc import x, y For linear expressions, the symbol can be isolated: >>> f(x - 2 < 0, x) x < 2 >>> f(-x - 6 < x, x) x > -3 Sometimes nonlinear relationships will be False >>> f(x**2 + 4 < 0, x) False Or they may involve more than one region of values: >>> f(x**2 - 4 < 0, x) (-2 < x) & (x < 2) To restrict the solution to a relational, set linear=True and only the x-dependent portion will be isolated on the left: >>> f(x**2 - 4 < 0, x, linear=True) x**2 < 4 Division of only nonzero quantities is allowed, so x cannot be isolated by dividing by y: >>> y.is_nonzero is None # it is unknown whether it is 0 or not True >>> f(x*y < 1, x) x*y < 1 And while an equality (or inequality) still holds after dividing by a non-zero quantity >>> nz = Symbol('nz', nonzero=True) >>> f(Eq(x*nz, 1), x) Eq(x, 1/nz) the sign must be known for other inequalities involving > or <: >>> f(x*nz <= 1, x) nz*x <= 1 >>> p = Symbol('p', positive=True) >>> f(x*p <= 1, x) x <= 1/p When there are denominators in the original expression that are removed by expansion, conditions for them will be returned as part of the result: >>> f(x < x*(2/x - 1), x) (x < 1) & Ne(x, 0) rrcSsPz0|||}|tjkr|WS|dkr,WdS|WStk rJtjYSXdS)NTF)rrNaNr~)ierHrXrrCrCrDclassifys  z#_solve_inequality..classifyNr#T)Zas_AddF)r"r!)linear)rrrr_r6r^rr5rZdegreerrr,r2rrmrer.r0rrZas_independentris_zeroZ is_negativeZ is_positiver`rb_solve_inequalityr r*r3)rrHrrrrZoorjrGZokooZoknoornrr_bZaxZefrZbeginning_denomsZcurrent_denomsrZcrXrCrCrDrsJ                 $ rc s:ii}}g}|D]}|j|j}}|t}t|dkrD|nF|j|@} t| dkr~| |tt |d|qn t t d| r| g||fq|fdd} | rtdd| Dr| g||fq|tt |d|qdd |D} d d |D} t| | |S) Nr#rzZ inequality has more than one symbol of interest. cs |o|jp|jo|jj Srp)rVZ is_Functionrtrurv)ur[rCrDrs z&_reduce_inequalities..css|]}t|tVqdSrp)r*rrFrXrCrCrDrqsz'_reduce_inequalities..cSsg|]\}}t|g|qSrC)rmrFr\rgrCrCrDrIsz(_reduce_inequalities..cSsg|]\}}t||qSrC)rrrCrCrDrIs)r^r`Zatomsrrpoprr3rr r2rZ is_polynomial setdefaultfindritemsr) rsymbolsZ poly_partZabs_partotherZ inequalityrjr8genscommon componentsZ poly_reducedZ abs_reducedrCr[rD_reduce_inequalitiesrs,        rcsPt|s|g}dd|D}tjdd|D}t|s@|g}t|pJ||@}tdd|Drnttddd|Dfd d|D}fd d |D}g}|D]~}t|tr||j |j d }n|d krt |d }|dkrqn|dkrt jS|j jrtd|||q|}~t||}|ddDS)aEReduce a system of inequalities with rational coefficients. Examples ======== >>> from sympy.abc import x, y >>> from sympy import reduce_inequalities >>> reduce_inequalities(0 <= x + 3, []) (-3 <= x) & (x < oo) >>> reduce_inequalities(0 <= x + y*2 - 1, [x]) (x < oo) & (x >= 1 - 2*y) cSsg|] }t|qSrC)rrrCrCrDrIsz'reduce_inequalities..cSsg|] }|jqSrC)rrrCrCrDrIscss|]}|jdkVqdS)FNrrrCrCrDrqsz&reduce_inequalities..zP inequalities cannot contain symbols that are not real. cSs&i|]}|jdkr|t|jddqS)NTr)r}rnamerrCrCrD s z'reduce_inequalities..csg|]}|qSrCrrZrecastrCrDrIscsh|]}|qSrCrrrrCrD sz&reduce_inequalities..rrTFr cSsi|]\}}||qSrCrC)rFkrrCrCrDrs)rrrNanyr~rr*r rrr^r,r_r rr0r-r2r3rrr)rrrZkeeprXrrCrrDreduce_inequalitiessB        r)T)F)9__doc__rKZsympy.calculus.utilrrrZ sympy.corerrrZsympy.core.exprtoolsrZsympy.core.relationalr r r r Zsympy.sets.setsr rrrZsympy.core.singletonrZsympy.core.functionrZ$sympy.functions.elementary.complexesrrZ sympy.logicrZ sympy.polysrrrZsympy.polys.polyutilsrZsympy.solvers.solvesetrrZsympy.utilities.iterablesrrZsympy.utilities.miscrrErJrTrmrrr/rerrrrrCrCrCrDs:      [B ZG)! .-